(V+4)^2=2v^2-3v+44

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Solution for (V+4)^2=2v^2-3v+44 equation: 



(+4)^2=2V^2-3V+44

We move all terms to the left:

(+4)^2-(2V^2-3V+44)=0

We add all the numbers together, and all the variables

-(2V^2-3V+44)+4^2=0

We add all the numbers together, and all the variables

-(2V^2-3V+44)+16=0

We get rid of parentheses

-2V^2+3V-44+16=0

We add all the numbers together, and all the variables

-2V^2+3V-28=0

a = -2; b = 3; c = -28;
Δ = b2-4ac
Δ = 32-4·(-2)·(-28)
Δ = -215
Delta is less than zero, so there is no solution for the equation

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